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0MS的递归#include<iostream.h> int r,c,a[101][101],flag[101][101]; int huaxue(int i,int j) { int temp,max=1; if(flag[i][j]!=-1) return flag[i][j]; if(a[i][j]>a[i-1][j]&&i>1) { temp=huaxue(i-1,j); if(max<temp+1) max=temp+1; } if(a[i][j]>a[i][j-1]&&j>1) { temp=huaxue(i,j-1); if(max<temp+1) max=temp+1; } if(a[i][j]>a[i+1][j]&&i<r) { temp=huaxue(i+1,j); if(max<temp+1) max=temp+1; } if(a[i][j]>a[i][j+1]&&j<c) { temp=huaxue(i,j+1); if(max<temp+1) max=temp+1; } flag[i][j]=max; return max; } void main() { int i,j,temp,max=0; cin>>r>>c; for(i=1;i<=r;i++) for(j=1;j<=c;j++) {cin>>a[i][j]; flag[i][j]=-1; } for(i=1;i<=r;i++) for(j=1;j<=c;j++) {temp=huaxue(i,j); if(max<temp) max=temp; } cout<<max<<endl; } Followed by:
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