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Re:两个细节

Posted by piratex at 2007-03-04 16:04:57 on Problem 1012
In Reply To:两个细节 Posted by:zsu_pierre at 2007-01-10 11:22:09
re~
照你说的死算
不需要那种本地算结果然后打表
也可以通过,尽管是765ms- -!

另外我没有算k=14这种情况。。如果有那应该会超时~

> 1、测试数据含有很多重复。所以先将结果算一次存储数组中。然后输入再返回输出较好。
> 2、查找结果时候发现规律:检测数据必须是k+1倍数或者k+1的倍数+1这样就可以见范围缩小到k+1分之2;
> 3、也是较多提到的,只需要检查kill的那个是否小于k+1和剩下的是否等于k。。。至于什么链表不链表没有关系~~

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