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Re:这题判定的不严a

Posted by jxwking2010 at 2006-07-24 20:46:43 on Problem 1477
In Reply To:这题判定的不严a Posted by:jxwking2010 at 2006-07-24 20:43:34
要是只用意移一步
应输出   The minimum number of move is 1 是move 而不是moves  还用空行,不安他说的也AC了。。。。。我无语
#include <stdio.h>
#include <math.h>
int main()
{
  int n,h; 
  int a[100]; 
  int i,j=0,k,sum;
  while(0!=scanf("%d",&n))
  {  
	  if(n==0)break;
	  sum=0;
    for(i=0;i<n;i++)              //input
	{
		scanf("%d",&a[i]);
        sum+=a[i];
	}
    
   h=sum/n;
  k=0;
   for(i=0;i<n;i++)
   {
	   k+=fabs(h-a[i]);
   }
   j++;
   if(j>1)printf("\n");
   printf("Set #%d\n",j); 
   printf("The minimum number of moves is %d.\n",k/2);
   
    
  }

  return 0;
}

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