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一定要先把14个数算一遍，用数组存起来才能过剪枝正如tangjuntianawj所说（不减也能过） 在最后一个坏人出队时，报数的人只有两种可能，第一个好人，或者最后一个坏人，所以报的数只能是k+1的倍数或者是k+1的倍数加1，而倒数第二个人的死，以此类推，有这个剪枝，只要有第一步，就可出解了 Followed by: Post your reply here: |
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