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我有好办法在最后一个坏人出队时，报数的人只有两种可能，第一个好人，或者最后一个坏人，所以报的数只能是k+1的倍数或者是k+1的倍数加1，而倒数第二个人的死，以此类推，有这个剪枝，只要有第一步，就可出解了 Followed by:
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