| ||||||||||
Online Judge | Problem Set | Authors | Online Contests | User | ||||||
---|---|---|---|---|---|---|---|---|---|---|
Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest |
按照普通的DP方法AC了,此题很多细节需要注意,程序仅供参考。#include <iostream> using namespace std; const short maxn=5001; char s[maxn]; int i,j,k,n; short f[maxn][maxn]; int main() { scanf("%d",&n); scanf("%s",s+1); memset(f,0,sizeof(f)); for(i=1;i<n;i++) for(j=1;j<=n-i;j++) { k=j+i; if(s[j]==s[k]) f[j][k]=f[j+1][k-1]; else f[j][k]=((f[j+1][k]<f[j][k-1])?f[j+1][k]:f[j][k-1])+1; } printf("%d\n",f[1][n]); return 0; } Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator